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lehrkraefte:blc:math-2021hw:zusatzaufgaben-potenzen [2021/09/02 11:38] Ivo Blöchliger |
lehrkraefte:blc:math-2021hw:zusatzaufgaben-potenzen [2021/09/02 11:38] (current) Ivo Blöchliger |
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| - | \frac{\left(2\cdot 121+1\right)^3}{81^4}\cdot\frac{3}{1} = \frac{243^3}{\left(3^4\right)^4}\cdot 3 = \frac{\left(3^5\right)^3}{3^{16}}\cdot 3 = \frac{3^{15}}{3^{16}} \cdot 3 = 1$$ | + | \frac{\frac{\left(2\cdot(5+6)^2+1\right)^3}{81^4}}{\frac{1}{3}} = \frac{\left(2\cdot 121+1\right)^3}{81^4}\cdot\frac{3}{1} = \frac{243^3}{\left(3^4\right)^4}\cdot 3 = \frac{\left(3^5\right)^3}{3^{16}}\cdot 3 = \frac{3^{15}}{3^{16}} \cdot 3 = 1$$ |
| </ | </ | ||