lehrkraefte:blc:miniaufgaben

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lehrkraefte:blc:miniaufgaben [2021/09/16 17:34]
Ivo Blöchliger [20. September 2021 bis 24. September 2021]
lehrkraefte:blc:miniaufgaben [2021/09/16 17:44]
Ivo Blöchliger [20. September 2021 bis 24. September 2021]
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 === Donnerstag 23. September 2021 === === Donnerstag 23. September 2021 ===
 Ausrechnen, Resultat als gekürzter Bruch:<JS>miniAufgabe("#exonumbercrunch2","#solnumbercrunch2", Ausrechnen, Resultat als gekürzter Bruch:<JS>miniAufgabe("#exonumbercrunch2","#solnumbercrunch2",
-[["$\\displaystyle \\frac{\\frac{2}{\\frac{26}{17}}+\\frac{-5}{\\frac{13}{3}}}{\\frac{-\\frac{15}{4}}{-6}+\\frac{-\\frac{7}{2}}{4}}$", "$\\displaystyle \\frac{\\frac{2}{\\frac{26}{17}}+\\frac{-5}{\\frac{13}{3}}}{\\frac{-\\frac{15}{4}}{-6}+\\frac{-\\frac{7}{2}}{4}} = \\frac{2\\cdot\\frac{17}{26}+-5\\cdot\\frac{3}{13}}{-\\frac{15}{4}\\cdot-\\frac{1}{6}+-\\frac{7}{2}\\cdot\\frac{1}{4}}  = \\frac{\\frac{17}{13}-\\frac{15}{13}}{\\frac{5}{8}-\\frac{7}{8}}  = \\frac{\\frac{2}{13}}{-\\frac{1}{4}} = \\frac{2}{13} \\cdot -4 = -\\frac{8}{13}$"], ["$\\displaystyle \\frac{\\frac{-\\frac{10}{3}}{8}+\\frac{-4}{-\\frac{8}{3}}}{\\frac{3}{\\frac{12}{5}}+\\frac{\\frac{7}{2}}{-7}}$", "$\\displaystyle \\frac{\\frac{-\\frac{10}{3}}{8}+\\frac{-4}{-\\frac{8}{3}}}{\\frac{3}{\\frac{12}{5}}+\\frac{\\frac{7}{2}}{-7}} = \\frac{-\\frac{10}{3}\\cdot\\frac{1}{8}+-4\\cdot-\\frac{3}{8}}{3\\cdot\\frac{5}{12}+\\frac{7}{2}\\cdot-\\frac{1}{7}}  = \\frac{-\\frac{5}{12}+\\frac{3}{2}}{\\frac{5}{4}-\\frac{1}{2}}  = \\frac{\\frac{13}{12}}{\\frac{3}{4}} = \\frac{13}{12} \\cdot \\frac{4}{3} = \\frac{13}{9}$"], ["$\\displaystyle \\frac{\\frac{-\\frac{16}{7}}{-2}+\\frac{-9}{\\frac{7}{2}}}{\\frac{-\\frac{13}{2}}{-7}+\\frac{-\\frac{12}{7}}{-8}}$", "$\\displaystyle \\frac{\\frac{-\\frac{16}{7}}{-2}+\\frac{-9}{\\frac{7}{2}}}{\\frac{-\\frac{13}{2}}{-7}+\\frac{-\\frac{12}{7}}{-8}} = \\frac{-\\frac{16}{7}\\cdot-\\frac{1}{2}+-9\\cdot\\frac{2}{7}}{-\\frac{13}{2}\\cdot-\\frac{1}{7}+-\\frac{12}{7}\\cdot-\\frac{1}{8}}  = \\frac{\\frac{8}{7}-\\frac{18}{7}}{\\frac{13}{14}+\\frac{3}{14}}  = \\frac{-\\frac{10}{7}}{\\frac{8}{7}} = -\\frac{10}{7} \\cdot \\frac{7}{8} = -\\frac{5}{4}$"], ["$\\displaystyle \\frac{\\frac{\\frac{13}{2}}{5}+\\frac{-4}{\\frac{20}{9}}}{\\frac{-\\frac{20}{3}}{8}+\\frac{7}{\\frac{14}{3}}}$", "$\\displaystyle \\frac{\\frac{\\frac{13}{2}}{5}+\\frac{-4}{\\frac{20}{9}}}{\\frac{-\\frac{20}{3}}{8}+\\frac{7}{\\frac{14}{3}}} = \\frac{\\frac{13}{2}\\cdot\\frac{1}{5}+-4\\cdot\\frac{9}{20}}{-\\frac{20}{3}\\cdot\\frac{1}{8}+7\\cdot\\frac{3}{14}}  = \\frac{\\frac{13}{10}-\\frac{9}{5}}{-\\frac{5}{6}+\\frac{3}{2}}  = \\frac{-\\frac{1}{2}}{\\frac{2}{3}} = -\\frac{1}{2} \\cdot \\frac{3}{2} = -\\frac{3}{4}$"], ["$\\displaystyle \\frac{\\frac{\\frac{19}{4}}{-4}+\\frac{\\frac{7}{8}}{2}}{\\frac{\\frac{3}{5}}{-4}+\\frac{\\frac{3}{2}}{2}}$", "$\\displaystyle \\frac{\\frac{\\frac{19}{4}}{-4}+\\frac{\\frac{7}{8}}{2}}{\\frac{\\frac{3}{5}}{-4}+\\frac{\\frac{3}{2}}{2}} = \\frac{\\frac{19}{4}\\cdot-\\frac{1}{4}+\\frac{7}{8}\\cdot\\frac{1}{2}}{\\frac{3}{5}\\cdot-\\frac{1}{4}+\\frac{3}{2}\\cdot\\frac{1}{2}}  = \\frac{-\\frac{19}{16}+\\frac{7}{16}}{-\\frac{3}{20}+\\frac{3}{4}}  = \\frac{-\\frac{3}{4}}{\\frac{3}{5}} = -\\frac{3}{4} \\cdot \\frac{5}{3} = -\\frac{5}{4}$"], ["$\\displaystyle \\frac{\\frac{-\\frac{10}{3}}{-4}+\\frac{\\frac{16}{7}}{-3}}{\\frac{4}{\\frac{14}{3}}+\\frac{-\\frac{18}{7}}{4}}$", "$\\displaystyle \\frac{\\frac{-\\frac{10}{3}}{-4}+\\frac{\\frac{16}{7}}{-3}}{\\frac{4}{\\frac{14}{3}}+\\frac{-\\frac{18}{7}}{4}} = \\frac{-\\frac{10}{3}\\cdot-\\frac{1}{4}+\\frac{16}{7}\\cdot-\\frac{1}{3}}{4\\cdot\\frac{3}{14}+-\\frac{18}{7}\\cdot\\frac{1}{4}}  = \\frac{\\frac{5}{6}-\\frac{16}{21}}{\\frac{6}{7}-\\frac{9}{14}}  = \\frac{\\frac{1}{14}}{\\frac{3}{14}} = \\frac{1}{14} \\cdot \\frac{14}{3} = \\frac{1}{3}$"], ["$\\displaystyle \\frac{\\frac{\\frac{13}{2}}{-10}+\\frac{\\frac{7}{4}}{5}}{\\frac{\\frac{7}{6}}{-4}+\\frac{\\frac{15}{4}}{9}}$", "$\\displaystyle \\frac{\\frac{\\frac{13}{2}}{-10}+\\frac{\\frac{7}{4}}{5}}{\\frac{\\frac{7}{6}}{-4}+\\frac{\\frac{15}{4}}{9}} = \\frac{\\frac{13}{2}\\cdot-\\frac{1}{10}+\\frac{7}{4}\\cdot\\frac{1}{5}}{\\frac{7}{6}\\cdot-\\frac{1}{4}+\\frac{15}{4}\\cdot\\frac{1}{9}}  \\frac{-\\frac{13}{20}+\\frac{7}{20}}{-\\frac{7}{24}+\\frac{5}{12}}  = \\frac{-\\frac{3}{10}}{\\frac{1}{8}} = -\\frac{3}{10} \\cdot = -\\frac{12}{5}$"], ["$\\displaystyle \\frac{\\frac{\\frac{8}{21}}{-2}+\\frac{-\\frac{16}{7}}{-3}}{\\frac{3}{\\frac{7}{3}}+\\frac{-\\frac{15}{7}}{5}}$", "$\\displaystyle \\frac{\\frac{\\frac{8}{21}}{-2}+\\frac{-\\frac{16}{7}}{-3}}{\\frac{3}{\\frac{7}{3}}+\\frac{-\\frac{15}{7}}{5}} = \\frac{\\frac{8}{21}\\cdot-\\frac{1}{2}+-\\frac{16}{7}\\cdot-\\frac{1}{3}}{3\\cdot\\frac{3}{7}+-\\frac{15}{7}\\cdot\\frac{1}{5}}  = \\frac{-\\frac{4}{21}+\\frac{16}{21}}{\\frac{9}{7}-\\frac{3}{7}}  \\frac{\\frac{4}{7}}{\\frac{6}{7}} \\frac{4}{7} \\cdot \\frac{7}{6} = \\frac{2}{3}$"], ["$\\displaystyle \\frac{\\frac{\\frac{20}{7}}{-4}+\\frac{-10}{-\\frac{7}{2}}}{\\frac{-2}{-\\frac{7}{8}}+\\frac{-\\frac{15}{7}}{5}}$", "$\\displaystyle \\frac{\\frac{\\frac{20}{7}}{-4}+\\frac{-10}{-\\frac{7}{2}}}{\\frac{-2}{-\\frac{7}{8}}+\\frac{-\\frac{15}{7}}{5}} = \\frac{\\frac{20}{7}\\cdot-\\frac{1}{4}+-10\\cdot-\\frac{2}{7}}{-2\\cdot-\\frac{8}{7}+-\\frac{15}{7}\\cdot\\frac{1}{5}}  = \\frac{-\\frac{5}{7}+\\frac{20}{7}}{\\frac{16}{7}-\\frac{3}{7}}  = \\frac{\\frac{15}{7}}{\\frac{13}{7}} = \\frac{15}{7} \\cdot \\frac{7}{13} = \\frac{15}{13}$"], ["$\\displaystyle \\frac{\\frac{4}{\\frac{11}{5}}+\\frac{-\\frac{21}{11}}{3}}{\\frac{-3}{\\frac{8}{3}}+\\frac{-\\frac{7}{2}}{7}}$", "$\\displaystyle \\frac{\\frac{4}{\\frac{11}{5}}+\\frac{-\\frac{21}{11}}{3}}{\\frac{-3}{\\frac{8}{3}}+\\frac{-\\frac{7}{2}}{7}} \\frac{4\\cdot\\frac{5}{11}+-\\frac{21}{11}\\cdot\\frac{1}{3}}{-3\\cdot\\frac{3}{8}+-\\frac{7}{2}\\cdot\\frac{1}{7}}  = \\frac{\\frac{20}{11}-\\frac{7}{11}}{-\\frac{9}{8}-\\frac{1}{2}}  = \\frac{\\frac{13}{11}}{-\\frac{13}{8}} = \\frac{13}{11} \\cdot -\\frac{8}{13} = -\\frac{8}{11}$"]],+[["$\\displaystyle \\frac{\\frac{-\\frac{13}{2}}{8}+\\frac{-\\frac{7}{8}}{7}}{\\frac{-\\frac{19}{2}}{6}+\\frac{\\frac{5}{2}}{3}}$", "$\\displaystyle \\frac{\\frac{-\\frac{13}{2}}{8}+\\frac{-\\frac{7}{8}}{7}}{\\frac{-\\frac{19}{2}}{6}+\\frac{\\frac{5}{2}}{3}} = \\frac{-\\frac{13}{2}\\cdot\\frac{1}{8}+-\\frac{7}{8}\\cdot\\frac{1}{7}}{-\\frac{19}{2}\\cdot\\frac{1}{6}+\\frac{5}{2}\\cdot\\frac{1}{3}}  = \\frac{-\\frac{13}{16}-\\frac{1}{8}}{-\\frac{19}{12}+\\frac{5}{6}}  = \\frac{-\\frac{13}{16}-\\frac{2}{16}}{-\\frac{19}{12}+\\frac{10}{12}} = \\frac{-\\frac{15}{16}}{-\\frac{3}{4}} = -\\frac{15}{16} \\cdot -\\frac{4}{3} = \\frac{5}{4}$"], ["$\\displaystyle \\frac{\\frac{\\frac{16}{5}}{4}+\\frac{-\\frac{8}{3}}{8}}{\\frac{\\frac{14}{3}}{-10}+\\frac{\\frac{7}{3}}{-7}}$", "$\\displaystyle \\frac{\\frac{\\frac{16}{5}}{4}+\\frac{-\\frac{8}{3}}{8}}{\\frac{\\frac{14}{3}}{-10}+\\frac{\\frac{7}{3}}{-7}} = \\frac{\\frac{16}{5}\\cdot\\frac{1}{4}+-\\frac{8}{3}\\cdot\\frac{1}{8}}{\\frac{14}{3}\\cdot-\\frac{1}{10}+\\frac{7}{3}\\cdot-\\frac{1}{7}}  = \\frac{\\frac{4}{5}-\\frac{1}{3}}{-\\frac{7}{15}-\\frac{1}{3}}  = \\frac{\\frac{12}{15}-\\frac{5}{15}}{-\\frac{7}{15}-\\frac{5}{15}} = \\frac{\\frac{7}{15}}{-\\frac{4}{5}} = \\frac{7}{15} \\cdot -\\frac{5}{4} = -\\frac{7}{12}$"], ["$\\displaystyle \\frac{\\frac{-2}{-\\frac{5}{4}}+\\frac{-9}{\\frac{15}{4}}}{\\frac{-9}{\\frac{5}{2}}+\\frac{-6}{-\\frac{15}{2}}}$", "$\\displaystyle \\frac{\\frac{-2}{-\\frac{5}{4}}+\\frac{-9}{\\frac{15}{4}}}{\\frac{-9}{\\frac{5}{2}}+\\frac{-6}{-\\frac{15}{2}}} = \\frac{-2\\cdot-\\frac{4}{5}+-9\\cdot\\frac{4}{15}}{-9\\cdot\\frac{2}{5}+-6\\cdot-\\frac{2}{15}}  = \\frac{\\frac{8}{5}-\\frac{12}{5}}{-\\frac{18}{5}+\\frac{4}{5}}  = \\frac{\\frac{8}{5}-\\frac{12}{5}}{-\\frac{18}{5}+\\frac{4}{5}} = \\frac{-\\frac{4}{5}}{-\\frac{14}{5}} = -\\frac{4}{5} \\cdot -\\frac{5}{14} = \\frac{2}{7}$"], ["$\\displaystyle \\frac{\\frac{\\frac{11}{2}}{5}+\\frac{-\\frac{9}{2}}{9}}{\\frac{-\\frac{19}{2}}{7}+\\frac{-\\frac{3}{2}}{-3}}$", "$\\displaystyle \\frac{\\frac{\\frac{11}{2}}{5}+\\frac{-\\frac{9}{2}}{9}}{\\frac{-\\frac{19}{2}}{7}+\\frac{-\\frac{3}{2}}{-3}} = \\frac{\\frac{11}{2}\\cdot\\frac{1}{5}+-\\frac{9}{2}\\cdot\\frac{1}{9}}{-\\frac{19}{2}\\cdot\\frac{1}{7}+-\\frac{3}{2}\\cdot-\\frac{1}{3}}  = \\frac{\\frac{11}{10}-\\frac{1}{2}}{-\\frac{19}{14}+\\frac{1}{2}}  = \\frac{\\frac{11}{10}-\\frac{5}{10}}{-\\frac{19}{14}+\\frac{7}{14}} = \\frac{\\frac{3}{5}}{-\\frac{6}{7}} = \\frac{3}{5} \\cdot -\\frac{7}{6} = -\\frac{7}{10}$"], ["$\\displaystyle \\frac{\\frac{\\frac{8}{3}}{-4}+\\frac{-\\frac{4}{3}}{3}}{\\frac{-\\frac{8}{3}}{3}+\\frac{\\frac{16}{3}}{-8}}$", "$\\displaystyle \\frac{\\frac{\\frac{8}{3}}{-4}+\\frac{-\\frac{4}{3}}{3}}{\\frac{-\\frac{8}{3}}{3}+\\frac{\\frac{16}{3}}{-8}} = \\frac{\\frac{8}{3}\\cdot-\\frac{1}{4}+-\\frac{4}{3}\\cdot\\frac{1}{3}}{-\\frac{8}{3}\\cdot\\frac{1}{3}+\\frac{16}{3}\\cdot-\\frac{1}{8}}  = \\frac{-\\frac{2}{3}-\\frac{4}{9}}{-\\frac{8}{9}-\\frac{2}{3}}  = \\frac{-\\frac{6}{9}-\\frac{4}{9}}{-\\frac{8}{9}-\\frac{6}{9}} = \\frac{-\\frac{10}{9}}{-\\frac{14}{9}} = -\\frac{10}{9} \\cdot -\\frac{9}{14} = \\frac{5}{7}$"], ["$\\displaystyle \\frac{\\frac{-5}{\\frac{9}{2}}+\\frac{-\\frac{11}{9}}{-2}}{\\frac{-\\frac{13}{5}}{-2}+\\frac{\\frac{5}{2}}{-5}}$", "$\\displaystyle \\frac{\\frac{-5}{\\frac{9}{2}}+\\frac{-\\frac{11}{9}}{-2}}{\\frac{-\\frac{13}{5}}{-2}+\\frac{\\frac{5}{2}}{-5}} = \\frac{-5\\cdot\\frac{2}{9}+-\\frac{11}{9}\\cdot-\\frac{1}{2}}{-\\frac{13}{5}\\cdot-\\frac{1}{2}+\\frac{5}{2}\\cdot-\\frac{1}{5}}  = \\frac{-\\frac{10}{9}+\\frac{11}{18}}{\\frac{13}{10}-\\frac{1}{2}}  = \\frac{-\\frac{20}{18}+\\frac{11}{18}}{\\frac{13}{10}-\\frac{5}{10}} = \\frac{-\\frac{1}{2}}{\\frac{4}{5}} = -\\frac{1}{2} \\cdot \\frac{5}{4} = -\\frac{5}{8}$"], ["$\\displaystyle \\frac{\\frac{-6}{-\\frac{13}{2}}+\\frac{-\\frac{18}{13}}{2}}{\\frac{-\\frac{14}{13}}{-2}+\\frac{-2}{\\frac{13}{8}}}$", "$\\displaystyle \\frac{\\frac{-6}{-\\frac{13}{2}}+\\frac{-\\frac{18}{13}}{2}}{\\frac{-\\frac{14}{13}}{-2}+\\frac{-2}{\\frac{13}{8}}} = \\frac{-6\\cdot-\\frac{2}{13}+-\\frac{18}{13}\\cdot\\frac{1}{2}}{-\\frac{14}{13}\\cdot-\\frac{1}{2}+-2\\cdot\\frac{8}{13}}  = \\frac{\\frac{12}{13}-\\frac{9}{13}}{\\frac{7}{13}-\\frac{16}{13}}  = \\frac{\\frac{12}{13}-\\frac{9}{13}}{\\frac{7}{13}-\\frac{16}{13}} = \\frac{\\frac{3}{13}}{-\\frac{9}{13}} = \\frac{3}{13} \\cdot -\\frac{13}{9} = -\\frac{1}{3}$"], ["$\\displaystyle \\frac{\\frac{\\frac{19}{10}}{2}+\\frac{-\\frac{5}{2}}{5}}{\\frac{-\\frac{19}{2}}{10}+\\frac{\\frac{8}{5}}{8}}$", "$\\displaystyle \\frac{\\frac{\\frac{19}{10}}{2}+\\frac{-\\frac{5}{2}}{5}}{\\frac{-\\frac{19}{2}}{10}+\\frac{\\frac{8}{5}}{8}} = \\frac{\\frac{19}{10}\\cdot\\frac{1}{2}+-\\frac{5}{2}\\cdot\\frac{1}{5}}{-\\frac{19}{2}\\cdot\\frac{1}{10}+\\frac{8}{5}\\cdot\\frac{1}{8}}  = \\frac{\\frac{19}{20}-\\frac{1}{2}}{-\\frac{19}{20}+\\frac{1}{5}}  = \\frac{\\frac{19}{20}-\\frac{10}{20}}{-\\frac{19}{20}+\\frac{4}{20}} = \\frac{\\frac{9}{20}}{-\\frac{3}{4}} = \\frac{9}{20} \\cdot -\\frac{4}{3} = -\\frac{3}{5}$"], ["$\\displaystyle \\frac{\\frac{-4}{-\\frac{12}{7}}+\\frac{7}{\\frac{21}{4}}}{\\frac{\\frac{13}{3}}{-2}+\\frac{\\frac{7}{2}}{7}}$", "$\\displaystyle \\frac{\\frac{-4}{-\\frac{12}{7}}+\\frac{7}{\\frac{21}{4}}}{\\frac{\\frac{13}{3}}{-2}+\\frac{\\frac{7}{2}}{7}} = \\frac{-4\\cdot-\\frac{7}{12}+7\\cdot\\frac{4}{21}}{\\frac{13}{3}\\cdot-\\frac{1}{2}+\\frac{7}{2}\\cdot\\frac{1}{7}}  = \\frac{\\frac{7}{3}+\\frac{4}{3}}{-\\frac{13}{6}+\\frac{1}{2}}  = \\frac{\\frac{7}{3}+\\frac{4}{3}}{-\\frac{13}{6}+\\frac{3}{6}} = \\frac{\\frac{11}{3}}{-\\frac{5}{3}} = \\frac{11}{3} \\cdot -\\frac{3}{5} = -\\frac{11}{5}$"], ["$\\displaystyle \\frac{\\frac{\\frac{11}{7}}{-2}+\\frac{-2}{-\\frac{7}{4}}}{\\frac{-\\frac{5}{4}}{-3}+\\frac{-\\frac{5}{3}}{-2}}$", "$\\displaystyle \\frac{\\frac{\\frac{11}{7}}{-2}+\\frac{-2}{-\\frac{7}{4}}}{\\frac{-\\frac{5}{4}}{-3}+\\frac{-\\frac{5}{3}}{-2}} = \\frac{\\frac{11}{7}\\cdot-\\frac{1}{2}+-2\\cdot-\\frac{4}{7}}{-\\frac{5}{4}\\cdot-\\frac{1}{3}+-\\frac{5}{3}\\cdot-\\frac{1}{2}}  = \\frac{-\\frac{11}{14}+\\frac{8}{7}}{\\frac{5}{12}+\\frac{5}{6}}  = \\frac{-\\frac{11}{14}+\\frac{16}{14}}{\\frac{5}{12}+\\frac{10}{12}} = \\frac{\\frac{5}{14}}{\\frac{5}{4}} = \\frac{5}{14} \\cdot \\frac{4}{5} = \\frac{2}{7}$"]],
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  • lehrkraefte/blc/miniaufgaben.txt
  • Last modified: 2024/04/19 16:53
  • by Ivo Blöchliger