| [["$4x^{2}+4x-15 = 0$", "$a=4$, $b=4$, $c=-15$<br>\nDiskriminante $D = b^2-4ac = 256$. Positiv, es gibt also 2 Lösungen. $\\sqrt{D} = 16$<br>$x_1 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{5}{2}$ und $x_2 = \\frac{-b - \\sqrt{D}}{2a} = \\frac{3}{2}$."], ["$6x^{2}-5x-4 = 0$", "$a=6$, $b=-5$, $c=-4$<br>\nDiskriminante $D = b^2-4ac = 121$. Positiv, es gibt also 2 Lösungen. $\\sqrt{D} = 11$<br>$x_1 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{1}{2}$ und $x_2 = \\frac{-b - \\sqrt{D}}{2a} = \\frac{4}{3}$."], ["$6x^{2}+x-15 = 0$", "$a=6$, $b=-1$, $c=-15$<br>\nDiskriminante $D = b^2-4ac = 361$. Positiv, es gibt also 2 Lösungen. $\\sqrt{D} = 19$<br>$x_1 = \\frac{-b - \\sqrt{D}}{2a} = \\frac{5}{3}$ und $x_2 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{3}{2}$."], ["$6x^{2}+13x+6 = 0$", "$a=6$, $b=13$, $c=6$<br>\nDiskriminante $D = b^2-4ac = 25$. Positiv, es gibt also 2 Lösungen. $\\sqrt{D} = 5$<br>$x_1 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{3}{2}$ und $x_2 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{2}{3}$."], ["$4x^{2}+4x-3 = 0$", "$a=4$, $b=4$, $c=-3$<br>\nDiskriminante $D = b^2-4ac = 64$. Positiv, es gibt also 2 Lösungen. $\\sqrt{D} = 8$<br>$x_1 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{3}{2}$ und $x_2 = \\frac{-b - \\sqrt{D}}{2a} = \\frac{1}{2}$."], ["$8x^{2}+14x+5 = 0$", "$a=8$, $b=14$, $c=5$<br>\nDiskriminante $D = b^2-4ac = 36$. Positiv, es gibt also 2 Lösungen. $\\sqrt{D} = 6$<br>$x_1 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{5}{4}$ und $x_2 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{1}{2}$."], ["$4x^{2}+16x+15 = 0$", "$a=4$, $b=16$, $c=15$<br>\nDiskriminante $D = b^2-4ac = 16$. Positiv, es gibt also 2 Lösungen. $\\sqrt{D} = 4$<br>$x_1 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{5}{2}$ und $x_2 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{3}{2}$."], ["$4x^{2}+8x+3 = 0$", "$a=4$, $b=8$, $c=3$<br>\nDiskriminante $D = b^2-4ac = 16$. Positiv, es gibt also 2 Lösungen. $\\sqrt{D} = 4$<br>$x_1 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{1}{2}$ und $x_2 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{3}{2}$."], ["$9x^{2}+18x+8 = 0$", "$a=9$, $b=18$, $c=8$<br>\nDiskriminante $D = b^2-4ac = 36$. Positiv, es gibt also 2 Lösungen. $\\sqrt{D} = 6$<br>$x_1 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{4}{3}$ und $x_2 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{2}{3}$."], ["$4x^{2}-4x-3 = 0$", "$a=4$, $b=-4$, $c=-3$<br>\nDiskriminante $D = b^2-4ac = 64$. Positiv, es gibt also 2 Lösungen. $\\sqrt{D} = 8$<br>$x_1 = \\frac{-b - \\sqrt{D}}{2a} = -\\frac{1}{2}$ und $x_2 = \\frac{-b - \\sqrt{D}}{2a} = \\frac{3}{2}$."]], | |